According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)

  • AIP = IG + Ah2
  • BIP = IG - Ah2
  • CIP = IG / Ah2
  • DIP = Ah2 / IG
Correct Answer : (A)

IP = IG + Ah2

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